Rumus trigonometri pada segitiga


ATURAN KOSINUS
a^{2}=b^{2}+c^{2}-2bc\cos A
b^{2}=a^{2}+c^{2}-2ac\cos B
c^{2}=a^{2}+b^{2}-2ab\cos C

\cos A= \frac{b^{2}+c^{2}-a^{2}}{2bc}

\cos B= \frac{a^{2}+c^{2}-b^{2}}{2ac}

\cos C= \frac{a^{2}+b^{2}-c^{2}}{2ab}

ATURAN SINUS

\frac{a}{\sin A}=\frac{b}{\sin B}=\frac{c}{\sin C}
atau

\frac{\sin A}{a}=\frac{\sin B}{b}=\frac{\sin C}{c}

Luas SEGITIGA

L=\frac{1}{2}bc \sin A=\frac{1}{2}ac\sin B=\frac{1}{2}ab\sin C

Rumus Heron
L=\sqrt{s(s-a)(s-b)(s-c)}, dimana s=\frac{1}{2}(a+b+c)
RUMUS SETENGAH SUDUT SEGITIGA

\sin \frac{A}{2}=\sqrt{\frac{(s-b)(s-c)}{bc}}

\sin \frac{B}{2}=\sqrt{\frac{(s-a)(s-c)}{ac}}

\sin \frac{C}{2}=\sqrt{\frac{(s-a)(s-b)}{ab}}

\cos \frac{A}{2}=\sqrt{\frac{s(s-a)}{bc}}

\cos \frac{B}{2}=\sqrt{\frac{s(s-b)}{ac}}

\cos \frac{C}{2}=\sqrt{\frac{s(s-c)}{ab}}

\tan \frac{A}{2}=\sqrt{\frac{(s-b)(s-c)}{s(s-a)}}

\tan \frac{B}{2}=\sqrt{\frac{(s-a)(s-c)}{s(s-b)}}

\tan \frac{C}{2}=\sqrt{\frac{(s-a)(s-b)}{s(s-c)}}

Tinggalkan Balasan

Isikan data di bawah atau klik salah satu ikon untuk log in:

Logo WordPress.com

You are commenting using your WordPress.com account. Logout / Ubah )

Gambar Twitter

You are commenting using your Twitter account. Logout / Ubah )

Foto Facebook

You are commenting using your Facebook account. Logout / Ubah )

Foto Google+

You are commenting using your Google+ account. Logout / Ubah )

Connecting to %s